Some time ago I saw an article about the concept of harvesting power from high-voltage transmission lines. The article reported disturbingly large voltages obtained from the equipment they set up, which led them to stop the experiment for the sake of safety (and legal protection). I was curious if I could figure out a way to predict the voltage we could expect from such a situation.
The electric system transmits power with alternating current (AC) at high voltages, which gets stepped-down by transformers when it is delivered to our houses. To see why the transmission is done at high voltage, we can imagine sending out a power P through lines with resistance R:
The power lost is inversely proportional to the square of the voltage, meaning raising the voltage can quickly decrease the power we lose to resistance.
When current travels through a wire, it produces a magnetic field in circles around the wire. The equation for this field is
where μ is the permeability of free space, I is the current in the wire, and ρ is the radial distance from the wire. For alternating current we can write
where I0 is the amplitude of the current and f is the oscillation frequency, 60 Hz in the US. If we set up our fence directly below the transmission line with the z-axis pointing along the fence and the y-axis pointing up toward the wire, then the B-field at this point will be
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where h is the height of the transmission wire, and we've replaced I0 with the power & voltage carried by the line. Now to get the voltage induced in the fence, we can use Ampere's Law:
Plugging in our B and integrating to get E gives
Electric field is measured in volts/meter, so this will tell us the relation between the length of our fence and the voltage we can expect between the two ends. The example case discussed in this Wikipedia article uses P = 1000 MW and V = 765 kV. This page gives the minimum height for wires carrying that voltage as 45 ft. Plugging in those values, along with the 60 Hz frequency I mentioned, gives 330 megavolts/meter, which is pretty insane! Now I did assume best (or maybe worst) case numbers in this calculation, but if you watch the video in the article that started this, the presenter seems a bit concerned with the size of the spark he gets at the end. Good (grounded) fences make good neighbors!